9 ! X, P and Q are flushed
10 ! because they are shared and accessible
20 ! a barrier implies a flush
21 ! X, P and Q are flushed
22 ! because they are shared and accessible
34 !$OMP PARALLEL REDUCTION(+: SUM) NUM_THREADS(2)
36 ! I, N and SUM were not flushed
37 ! because they were not accessible in F1
38 ! J was flushed because it was accessible
41 ! I, N, and SUM were not flushed
42 ! because they were not accessible in f2
43 ! J was flushed because it was accessible
44 SUM = SUM + I + J + P + N
57 IF (RESULT .NE. 30) THEN