core: remove redundant "override O := $(O)"

The top-level Makefile contains an "override O := $(O)" statement that
is purportedly required to make sure the O flag doesn't leak into the
environment of sub-makes. However, since commit 173135d, there is
already an "override O := ..." a few lines down. Therefore, the first
override is redundant.

Signed-off-by: Arnout Vandecappelle (Essensium/Mind) <arnout@mind.be>
Reviewed-by: Samuel Martin <s.martin49@gmail.com>
Signed-off-by: Thomas Petazzoni <thomas.petazzoni@free-electrons.com>

diff --git a/Makefile b/Makefile
index 4b494a33070e3fc7f05b8b9fbe07282412554fb9..cb030d46cfcb1013f1933310c4a56694eeca7be2 100644 (file)
--- a/Makefile
+++ b/Makefile
@@ -34,13 +34,6 @@ SHELL := $(shell if [ -x "$$BASH" ]; then echo $$BASH; \
 # build by preventing it from being forwarded to sub-make calls.
 ifneq ("$(origin O)", "command line")
 O := $(CURDIR)/output
-else
-# Strangely enough O is still passed to submakes with MAKEOVERRIDES
-# (with make 3.81 atleast), the only thing that changes is the output
-# of the origin function (command line -> environment).
-# Unfortunately some packages don't look at origin (E.G. uClibc 0.9.31+)
-# To really make O go away, we have to override it.
-override O := $(O)
 endif
 
 # Check if the current Buildroot execution meets all the pre-requisites.